Editorial for WC '18 Contest 2 J1 - Alternate Access

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If $A < B$ ~A < B~, then Ethan must climb upwards $B-A$ ~B-A~ times, for a total energy cost of $U \times (B-A)$ ~U \times (B-A)~ joules.

Otherwise (if $A > B$ ~A > B~), he must climb downwards $A-B$ ~A-B~ times, for a total energy cost of $D \times (A-B)$ ~D \times (A-B)~ joules.

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